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Sunday, August 15, 2010

Atomic Structure Test for IIT Jee| Aieee | 11th Class and 12th Class

Descriptive Questions(Section –I)

Total Marks: 26+20=46

This section contains 6 questions. All questions are compulsory and marks will be awarded on the basis of approach towards questions:

Question No.1.

Similar to electron diffraction, neutron diffraction microscope is also used for the determination of the structure of molecules. If the wavelength used here is 800 pm, calculate the characteristic velocity associated with the neutron. (3 Marks)

Question No. 2.

Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the frequency of emission, (b) distance travelled by this radiation in 30 s (c) energy of quantum and (d) number of quanta present if it produces 2 J of energy. (6 Marks)

Question No.3.

The number of electrons, protons and neutrons in a species are equal to 18, 16 and 16 respectively. Assign the proper symbol to the species. (3 marks)

Question No.4.

Describe Bohr’s model of atom and explain its usefulness over Rutherford model of atom. (5 Marks)

Question No.5.

State and explain the following: (6 Marks)

Ø Aufbau Principle

Ø De Broglie’s relation

Ø Pauli Exclusion Principle

Question No.6.

What will be the wavelength of a ball of mass 0.1 kg moving with a velocity of 10 m s–1? (2 Marks)

Objective Type Questions (Section-II)

2 marks will be awarded to every right answer and 1 marks will be deducted for every wrong answer, No marks will be given on any unattempted question:

Q No.1

The energy of one mole of photons in (kilo joule/mole) of radiation whose frequency is 5*10^14 Hz is:

A) 199.51 B) 2008 C) 2099.51 D) 1990.51

Q No.2

For a p-electron, orbital angular moment is:

(A) √2h (B) h (C) √6h (D) 2h

Q.No.3

If the radius of 2nd Bohr orbit of hydrogen atom is r2. The radius of third Bohr orbit will be:

(A) 4/9r2 (B) 4r2 (C) 9/4r2 (D) 9r2

Q.NO.4

The velocity of electron in the ground state hydrogen atom is 2.18 x 106 ms–1. Its velocity in the second orbit would be:

(A) 1.09 x 106 ms–1 (B) 4.38 x 106 ms–1 (C) 5.5 x 105 ms–1 (D) 8.76 x 106 ms–1

Q.NO.5

Cathode rays were discovered by:

A) William Crookes B) Rutherford C)Chadwick D)None of these

Q.NO.6

Cathode rays are produced when the pressure in the discharge tube is:

A) 10000 mm of Hg B) 10-2 mm of Hg C) 100 mm of Hg d) None of these

Q.No.7

Iselectronic species are:

A) Na+, F- B) Al3+, O2- C) N,O D) A and B

Q.No.8

2P orbital have:

A) n=1,l=1 B) n=2,l=2 C) n=2,l=1 D) None of these

Q.No.9

Which of the following sets of quantum numbers are not possible?

(a) n = 0, l = 0, ml = 0, ms = + ½

(b) n = 1, l = 0, ml = 0, ms = – ½

(c) n = 1, l = 1, ml = 0, ms = + ½

(d) n = 2, l = 1, ml = 0, ms = – ½

A) a, b B)a, c C) a, d D)None of these

Q.No.10

The electronic configuration of Cu is:

A) [Ar] 4s1, 3d10 B) [Ar] 4s2, 3d9 C) [Ar] 3d10 ,4s2 D)None of these

Moles Test for IIT Jee| AIEEE | 11th Class| 12th Class

Descriptive Questions(Section –I)

Total Marks: 35+10=45

This section contains 8 questions. All questions are compulsory and marks will be awarded on the basis of approach towards questions:

Question No.1

Define the different methods used for expressing concentration of a solution. (5 Marks)

Question No.2

Calculate the amount of water (g) produced by the combustion of 16 g of methane. (2 Marks)

Question No.3

A solution is prepared by adding 2 g of a substance A to 18 g of water. Calculate the mass per cent of the solute. (3 Marks)

Question No.4

State and explain the following with common example (12 Marks)

1. Law of conservation of mass

2. Law of Gay Lussac’s Law

3. Avogadro’s Law

4. Law of Multiple Proportion

Question N0.5

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1. (3 Marks)

Question No.6

Prove Avogadro’s number is equal to 6.02*10^23. (2 Marks)

Question No.7

What is limiting reagent? What is the significance of limiting reagent in chemical reaction? (3 Marks)

Question No.8

Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with aqueous hydrochloric acid according to the reaction:

4 HCl (aq) + MnO2(s) →2H2O (l) + MnCl2(aq) + Cl2 (g)

How many grams of HCl react with 5.0 g of manganese dioxide? (5 Marks)

Objective Type Questions (Section-II)

2 marks will be awarded to every right answer and 1 marks will be deducted for every wrong answer, No marks will be given on any unattempted question:

Q.No.1.

The percentage of copper and oxygen in samples of CuO obtained by different methods is found to be same. This illustrates the law:

A) Multiple Proportion B)Conservation Of Mass C) Gay Lussac’s Law D) None of these

Q.No.2

The number of electrons in one mole of hydrogen molecule is:

A) 6.02*10^23 B) 12.04*10^23 C)18.06*10^23 D)None of these

Q.No.3

The percentage of oxygen in NaOH is:

A)40 B)60 C)8 D)10

Q.No.4

Normality of 2M sulphuric acid is:

A) 2N B) 4N C) N/2 D) N/4

Q.No.5

How many atoms are contained in one mole of sucrose (C12H22O11):

A) 45*6.02*1023 B) 5*6.02*1023 C)10*6.02*1023 D)None of these

Why pressure inside the discharge tube is very low?

Why pressure inside the discharge tube is very low?

If the pressure is very high then electrons get scattered (due to the presence of gas molecule) from their path and mean free path will be very less will be very less for them.

Why we called tube as "discharge tube"?

Why we called tube as discharge tube?

Because in the tube we two have two electrodes cathode and anode and electrons emitted from cathode end towards anode end. It means electrons get discharge from cathode end and hence we generally say tube as discharge tube.

Sunday, August 8, 2010

Full Description of Shaving Cream

Shaving creams are applied on face for avoiding razor burns while shaving.

The major types are:- 1.Foam or Gel( use alcohol as major lubricant which causes excessive dryness to skin)

2.Tube and Tube based( glycerine is the major lubricant, so less dry on skin)

According to Burma Shave chronicler Frank Rowsome, Jr., modern shaving cream began with Burma Shave, which achieved high sales volume almost immediately after it was introduced. Prior to that time, lather was produced from a bar, and was basically another form of soap.

Manufacturing soap itself is an ancient craft—the word comes from the Old English word sape. The Holy Roman Emperor Charlemagne recognized soapmakers as craftsman. In the fourteenth and fifteenth centuries soap was made at Savona, Italy. The modern French, Spanish and German words for soap (savon, jabon, and seife, respectively) are cognates of the name of that town.

The early American settlers manufactured soap at home, by mixing and heating animal fat with lye in a pot. This "open kettle" method of soap making was popular for years.

Soap was used for shaving through the early 1800s. In 1840, a concentrated soap that foamed was sold in tablets by Vroom and Fowler, whose Walnut Oil Military Shaving Soap was probably the first soap made especially for shaving. A century later, as the United States entered World War II, animal fats of relatively uncontrolled type and quality were still being used to make soap.

In addition to raising concerns about the quality of soap, World War II contributed to the invention of the spray can. Aerosol containers were first invented during the war as a device for dealing with insects carrying malaria and other diseases. When the first aerosol shaving cream appeared in 1950, it captured almost one fifth of the market for shaving preparations within a short time. Today, aerosol preparations dominate the shaving cream market.

Raw Materials

The goal of any shaving preparation is to wet and soften the hair to be shaved, cushion the effect of the razor, and provide a residual film to soothe the skin. This film should be of the proper pH value: neither excessively alkaline nor overly acidic, it should correspond to the skin's pH level.

Many manufacturers say that the recipes for shaving cream are carefully guarded secrets. However, the secrecy revolves mostly around the quantities in which standard ingredients are used, and the choice of substitutes for the few ingredients that are variable. By law, ingredients are listed right on the container, except for perfumes.

A standard recipe contains approximately 8.2 percent stearic acid, 3.7 percent triethanolamine,. 5 percent lanolin, 2 percent glycerin, 6 percent polyoxyethylene sorbitan monostearate, and 79.6 percent water.

Stearic acid is one of the main ingredients in soap making, and triethanolamine is a surfactant, or surface-acting agent, which does the job of soap, rather much better. While one end of a surfactant molecule attracts dirt and grease, the other end attracts water. Lanolin and polyoxyethylene sorbitan monostearate are both emulsifiers which hold water to the skin, while glycerin, a solvent and an emollient, renders skin softer and more supple.

Common substitutes for the third, fourth, and fifth ingredients listed above include laureth 23 and lauryl sulfate (both sudsing and foaming agents), waxes, cocamides (which cleanse and aid foaming), and lanolin derivatives (emulsifiers). Most ingredients are powdered or flaked, although lanolin, lanolin derivatives, and cocamides are liquids.

The differences between one brand of shaving cream and another amount to adjustments in the proportions of ingredients and in the processing method (longer or shorter heating times, storage of the finished product, and so on), and choice of ingredients such as emulsifiers or perfumes. Also important is the choice of aerosol propellant. Some mixtures contain more than one propellant; most common are butane, isobutane, and propane. Though the wide range of choices for ingredients is well known, the exact combinations of ingredients represent the highest level of "magic" in modern chemistry.

The Manufacturing Process

The modern manufacture of shaving cream is a carefully controlled process. Although carried out on a large scale, its manufacture resembles a laboratory procedure involving only small quantities of ingredients. There are two main phases to the manufacturing process.

1. In the first phase, the fatty or oily portions—stearic acid, lanolin, and polyoxyethylene sorbitan monostearate—are heated in a jacketed kettle. The jacketed kettle resembles a double boiler: one container, placed inside another, is heated while steam is circulated through the outer container. Inside the interior kettle, are blades that revolve to mix the oils as they are heated.

2. After the first group of ingredients has turned smooth, the steam is released from the outer container of the kettle, and the mixture is allowed to cool.

3. The second phase of manufacture begins when the mixture has cooled. Most of the remaining ingredients—water, glycerin, and triethanolamine—are added now, and mixed

4. When the temperature of mixture is balanced, perfumes or other scents can be added. Because perfumes consist primarily of highly volatile oils, they would evaporate if added when the blend was still warm. The formulas for perfumes, which can contain more than 200 different ingredients, come closer to being trade secrets than information about shaving cream itself.

5. The mixture, still being stirred, is allowed to cool further, until it reaches room temperature. Now a thickening white mass of highly viscous liquid, it is forced through a silk or stainless steel screen to eliminate any lumps that may have formed in the mixing process, and to catch the rare impurity or foreign object such as a small wood splinter.

6. If this particular mixture is designated for tube packaging, it is now placed in a tube and fitted with a cap. After the bottom of the tube has been crimped, the product is ready for shipment and stocking on a store shelf.

7. When the desired product is an aerosol spray, the shaving cream is poured into an open can. Next a valve and a cover are fitted onto the can and forced downward to form a seal. Propellant is then forced into the can through the valve. Most shaving preparations contain between four and five percent propellant; a larger amount would dry the shaving cream as it came out of the can, rendering it unusable. A small amount of material is intentionally released (purged) to relieve excess pressure, and the can is tested in water to make sure that the valve is holding tightly. The can is now ready

Quality Control

Water quality must be checked carefully. Most manufacturers make sure the water they use is pure by exposing the water to ultraviolet light or using distilled water. Having a microbiologist on site to test the water and the final product is common in the industry.

In a typical aerosol can, the shaving cream ingredients occupy only a small portion of the can. The propellant or gas occupies 4 to 5 percent of the can; a larger amount would dry the shaving cream as it came out of the can, rendering it unusable.

In a typical aerosol can, the shaving cream ingredients occupy only a small portion of the can. The propellant or gas occupies 4 to 5 percent of the can; a larger amount would dry the shaving cream as it came out of the can, rendering it unusable